Spring Cloud Feign 请求动态URL

FeignClient 中不要写url, 使用 @RequestLine修饰方法
调用地方必须引入 FeignClientConfiguration, 必须有Decoder, Encoder
调用类必须以构建函数(Constructor) 的方式注入 FeignClient 类
传入URL作为参数; 代码如下:

FeignClient类:

@FeignClient(name = "xxxxClient")
public interface XxxFeignClient {
    @RequestLine("POST")
    ResponseDto notifySomething(URI baseUri, ApproveNotifyDto notifyDto);

    @RequestLine("GET")
    ResponseDto getSomething(URI baseUri, XxxDto xxxDto);
}

ClientCaller类

@Slf4j
@Component
@Import(FeignClientsConfiguration.class)
public class CallerService {

    private XxxFeignClient xxxFeignClient;

    @Autowired
    public CallerService(Decoder decoder, Encoder encoder) {
        xxxFeignClient = Feign.builder()
            //.client(client)
            .encoder(encoder)
            .decoder(decoder)
            .target(Target.EmptyTarget.create(XxxFeignClient.class));
    }

    public ResponseDto notifySomething(String url, XxxxDto dto) throws URISyntaxException {
        return xxxFeignClient.notifySomething(new URI(url), dto);
    }


    public String test() throws URISyntaxException {
        String url = "http://localhost:9104/";
        return xxxFeignClient.getSomething(new URI(url));
    }
}

测试成功. 有点蛋疼.

参考链接:

https://stackoverflow.com/questions/43733569/how-can-i-change-the-feign-url-during-the-runtime

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