Swift JSON字符串和字典以及数组的互转

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Swift JSON字符串和字典以及数组的互转

1、JSONString转换为字典

// JSONString转换为字典
func getDictionaryFromJSONString(jsonString:String) ->NSDictionary{
    let jsonData:Data = jsonString.data(using: .utf8)!
    let dict = try? JSONSerialization.jsonObject(with: jsonData, options: .mutableContainers)
    if dict != nil {
        return dict as! NSDictionary
    }
    return NSDictionary()
}

2、JSONString转换为数组

func getArrayFromJSONString(jsonString:String) ->NSArray{
  let jsonData:Data = jsonString.data(using: .utf8)!
  let array = try? JSONSerialization.jsonObject(with: jsonData, options: .mutableContainers)
  if array != nil {
    return array as! NSArray
  }
  return array as! NSArray
}

3、字典转换为JSONString

/**
字典转换为JSONString
- parameter dictionary: 字典参数
- returns: JSONString
*/
func getJSONStringFromDictionary(dictionary:NSDictionary) -> String {
  if (!JSONSerialization.isValidJSONObject(dictionary)) {
    print("无法解析出JSONString")
    return ""
  }
  let data : NSData! = try? JSONSerialization.data(withJSONObject: dictionary, options: []) as NSData!
  let JSONString = NSString(data:data as Data,encoding: String.Encoding.utf8.rawValue)
  return JSONString! as String
}

4、数组转换为JSONString

//数组转json
func getJSONStringFromArray(array:NSArray) -> String {
  if (!JSONSerialization.isValidJSONObject(array)) {
    print("无法解析出JSONString")
    return ""
  }
  let data : NSData! = try? JSONSerialization.data(withJSONObject: array, options: []) as NSData!
  let JSONString = NSString(data:data as Data,encoding: String.Encoding.utf8.rawValue)
  return JSONString! as String
}